[TML] Thrust Distribution Field

[Anthony Jackson]

Craig Berry wrote:

> Yes, it really does. :>

No, it really doesn't ;) (though under relativistic conditions you can 
disagree about how much potential energy became kinetic energy).

> Now, start in the pre-acceleration rest frame of the ship.  The
> initial KE is all in the reaction mass: 0.5(1kg)(10m/s)^2 = 50J.  The
> final KE, with the reaction mass moving 11m/s and the ship 1m/s, is
> 0.5(1kg)(11m/s)^2 + 0.5(10kg)(1m/s)^2 = 60.5J + 50J = 110.5J  The
> change in KE is thus 60.5J.

Nope. The reaction mass is moving at 20m/s after acceleration, not 
11m/s, for a total energy of 0.5(1)(20)^2 + 0.5(10)(1)^2 = 205J. Change 
in KE: 155J
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