[TML] Alderson disk
shadow at shadowgard.com
shadow at shadowgard.com
Mon Dec 10 13:00:41 MST 2007
Did a rough calculation a bit ago. Looks like if I want the sun to
reach 45 degrees above the horizon at 1 AU from the center, the days
are going to be *really* long.
I get a figure of 48 hours from sunhigh to sunset. Which gives a
cycle like this (using A and B to represent the sides of the disk):
time A B
0 sunhigh midnight
48 sunset sunrise
96 midnight sunhigh
144 sunset sunrise
192 sunhigh midnight
That's just a hair extreme.
Also, the motion of the sun will be really non-linear. I'll be
writing a program to give time and angle at 1 AU later (ignoring
atmospheric refraction). Other latitudes can be worked out easily
from that.
If folks are interested in working on this, I'll stick stuff up on a
web page as we nail stuff down.
ps. to get 12 hours from sunhigh to sunset gives really low sun
angles. So if folks think the long days and nights can be worked
with, I'd rather keep them.
--
Leonard Erickson (aka shadow)
shadow at shadowgard dot com
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